ΔU=0 ⇒23R(Tf−T0)+1×25R(Tf−37 T0)=0 Tf=23 T0
JEE Main 2006 — Physics Thermodynamics
Two rigid boxes containing different ideal gases are placed on a table. Box A contains one mole of nitrogen at temperature T0, while Box B contains one mole of helium at temperature (7/3)T0. The boxes are then put into thermal contact with each other and heat flows between them until the gases reach a common final temperature. (Ignore the heat capacity of boxes). Then, the final temperature of the gases, Tf, in terms of T0 is
Held on 30 Apr 2006 · Verified 6 Jul 2026.
Tf=25 T0
Tf=73 T0
Tf=37 T0
Tf=23T0
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Work through every JEE Main Thermodynamics PYQ, year by year.