Father gives his X-chromosome to the daughter while Y-chromosome to the sons. In the case, only daughter and none of the sons are affected, the trait is X-linked. Since, daughters get the second copy of X-chromosomes from the mother who is normal and hence does not carry the affected allele of the trait. The trait is expressed in daughters under heterozygous condition, hence it is a X-linked dominant trait
A diseased man marries a normal woman. They get three daughter and five sons. All the daughter were diseased and sons were normal. The gene of this…
NEET UG 2002 — Zoology Principles of Inheritance and Variation
2002mcqmedium
A diseased man marries a normal woman. They get three daughter and five sons. All the daughter were diseased and sons were normal. The gene of this disease is:
Official previous-year question
Held on 30 Apr 2002 · Verified 9 Jul 2026.
Options
- A
sex-linked dominant
- B
sex-linked recessive
- C
sex-limited character
- D
autosomal dominant
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