β=dλD
β′=d′λD′
D′=2D,d′=2d
β′=2dλ×2D=d4λD
β′=4β
Fringe width becomes 4 times.
In Young’s double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is…
NEET UG 2020 — Physics Optics
2020mcqeasy
In Young’s double slit experiment, if the separation between coherent sources is halved and the distance of the screen from the coherent sources is doubled, then the fringe width becomes:
Official previous-year question
Held on 30 Apr 2020 · Verified 9 Jul 2026.
Options
- A
half
- B
four times
- C
one-fourth
- D
double
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