Given, u=−1.5f, now use the mirror formula for the concave mirror, in terms of distance between object and pole, the distance between image and pole and focal length,
u1+v1=f1⇒−1.5f1+v1=−f1
⇒v1=−f1+1.5f1⇒v1=1.5f−1.5+1=1.5f−0.5
⇒v=−3f.
An object is placed on the principal axis of a concave mirror at a distance of 1.5f (f is the focal length). The image will be at,
NEET UG 2020 — Physics Optics
2020mcqeasy
An object is placed on the principal axis of a concave mirror at a distance of 1.5f (f is the focal length). The image will be at,
Official previous-year question
Held on 30 Apr 2020 · Verified 9 Jul 2026.
Options
- A
−3f
- B
1.5f
- C
−1.5f
- D
3f
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