Case I:
Feq1+F1+F1
F1=Feq=2F
Case II:
F2=Feq=F
F1:F2=1:2
NEET UG 2019 — Physics Optics
Two similar thin equi-convex lenses of focal length f each are kept coaxially in contact with each other, such that the focal length of the combination is F1. When the space between the two lenses is filled with glycerin (which has the same refractive index (μ=1.5) as that of glass), then the equivalent focal length is F2. The ratio F1:F2 will be
Held on 30 Apr 2019 · Verified 9 Jul 2026.
2:1
1:2
2:3
3:4
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