The angular width of central maxima is given by 2θ=a2λ where, λ = wavelength of light used a= width of the slit For λ1=6000A˚,2θ=θ0 (given) For another light of wavelength λ2 (says), the angular wid th decreases by 30% so, 2θ=(100100−30)θ0=10070θ0=0.7θ0 As slit width is constant, so using Eq. (i) for these values, we get 0.7θ0θ0=λ2λ1⇒λ2=λ1×0.7=6000×0.7=4200A˚
Angular width of the central maxima in the Fraunhoffer diffraction for λ=6000 Å is θ_0. When the same slit is illuminated by another monochromatic…
NEET UG 2019 — Physics Optics
Angular width of the central maxima in the Fraunhoffer diffraction for λ=6000A˚ is θ0. When the same slit is illuminated by another monochromatic light, the angular width decreases by 30%. The wavelength of this light is
Held on 30 Apr 2019 · Verified 9 Jul 2026.
Options
- A
1800A˚
- B
4200A˚
- C
6000A˚
- D
420A˚
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