d=1mm=1×10−3m
D=1m.,λ=500×10−9m
Width of the central maximum = width of 10 maxima in YDSE
a2λD=d10λD
a=0.2d=0.2mm
In a double-slit experiment, the two slits are 1 mm apart and the screen is placed 1m away. A monochromatic light of wavelength 500 nm is used. What…
NEET UG 2015 — Physics Optics
2015mcqhard
In a double-slit experiment, the two slits are 1mm apart and the screen is placed 1m away. A monochromatic light of wavelength 500nm is used. What will be the width of each slit for obtaining ten maxima of double-slit within the central maxima of a single-slit pattern?
Official previous-year question
Held on 30 Apr 2015 · Verified 9 Jul 2026.
Options
- A
0.2mm
- B
0.1mm
- C
0.5mm
- D
0.02mm
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