To retrace its path light rays should fall normally on the reflecting surface. So
r2=0
⇒r1=A−r2⇒r1=A
Now applying snell rule between incident ray and refracted ray.
(1)sin(2A)=nsin(A)⇒2sinAcosA=nsinA
⇒n=2cosA
The angle of a prism is ‘ A ’. One of its refracting surfaces is silvered. Light rays falling at an angle of incidence 2A on the first surface…
NEET UG 2014 — Physics Optics
2014mcqmedium
The angle of a prism is ‘ A ’. One of its refracting surfaces is silvered. Light rays falling at an angle of incidence 2A on the first surface returns back through the same path after suffering reflection at the silvered surface. The refractive index μ, of the prism is:
Official previous-year question
Held on 30 Apr 2014 · Verified 9 Jul 2026.
Options
- A
2sinA
- B
2cosA
- C
21cosA
- D
tanA
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