Imax=4I0=K
at the other point, path difference =4λ
So, phase difference ϕ=λ2π×4λ=2π
I′=I0+I0+2I0I0cos2π
I′=2I0=2K
In the Young’s double slit experiment the intensity of light at a point on the screen where the path difference is λ is K, ( λ being the wave length of light used). The intensity at a point where the path difference is 4λ, will be:
Held on 30 Apr 2014 · Verified 9 Jul 2026.
K
4K
2K
Zero
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