In Young's double slit experiment fringe width β=dλD where D= distance between slit and screen d= distance between slit According to the question D is double →2D and d is half → 2d Ther New fringe wilth will be 2dλ×2D=d4λD=4(dλD)=β β1=4β i.e., becomes four times
In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits reduced to half. As a…
NEET UG 2013 — Physics Optics
2013mcqmedium
In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits reduced to half. As a result the fringe width:
Official previous-year question
Held on 30 Apr 2013 · Verified 9 Jul 2026.
Options
- A
is halved
- B
becomes four times
- C
remains unchanged
- D
is doubled
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