By mirror formula, image distance of A v1+u1=f1 
vA1+u1vA1+(−30)1vA=f1=−101=−15 cm Also image distance of C vC=−20 cm The length of image =∣vA−vC∣ =∣−15−(−20)∣ =5 cm
A rod of length 10 ~cm lies along the principal axis of a concave mirror of focal length 10 ~cm in such a way that its end closer to the pole is 20…
NEET UG 2012 — Physics Optics
2012mcqmedium
A rod of length 10 cm lies along the principal axis of a concave mirror of focal length 10 cm in such a way that its end closer to the pole is 20 cm away from the mirror. The length of the image is
Official previous-year question
Held on 30 Apr 2012 · Verified 9 Jul 2026.
Options
- A
10 cm
- B
15 cm
- C
2.5 cm
- D
5 cm
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