Given u=10 cm,y=15 cm f1=y1−u1f1=151−101f1=15010−15f1=150−5f=−30 cm
A conversing beam of rays is incident on a diverging lens. Having passed though the lens the rays intersect at a point 15 ~cm from the lens on the…
NEET UG 2011 — Physics Optics
A conversing beam of rays is incident on a diverging lens. Having passed though the lens the rays intersect at a point 15 cm from the lens on the opposite side. If the lens is removed the point where the rays meets will move 5 cm closer to the lens. The focal length of the lens is
Held on 30 Apr 2011 · Verified 9 Jul 2026.
Options
- A
−10 cm
- B
20 cm
- C
−30 cm
- D
5 cm
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