In general we have assumed μ=1.5 So, f=20 cm f1201y1yh0hihihi=y1+u1=y1+301=201−301=60010=60 cm=2=2×∣ho=4 cm Here, Image is real, inverted, magnified field and height of image is 4 cm.
A biconvex lens has a radius of curvature of magnitude 20 cm. Which one of the following options describe best the image formed of an object of height 2 cm placed 30 cm from the lens?
Held on 30 Apr 2011 · Verified 9 Jul 2026.
Virtual, upright, height =0.5 cm
Real, inverted, height =4 cm
Real, inverted, height =1 cm
Virtual, upright, height =1 cm
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