log(k1k2)=2.303REa( T11− T21)log(14)=2.303REa(3001−3301)Ea=30(log(4))×2.303×8.314×300×330=3.804×104 J/mol=38.04 kJ/mol
NEET UG 2024 — Chemistry Physical Chemistry
The rate of a reaction quadruples when temperature changes from 27∘C to 57∘C. Calculate the energy o activation. Given R=8.314 J K−1 mol−1,log4=0.6021
Held on 30 Apr 2024 · Verified 9 Jul 2026.
380.4 kJ/mol
3.80 kJ/mol
3804 kJ/mol
38.04 kJ/mol
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