(I) n=4,I=2,mI=−2,s=−21; represents 4d(n+I=6) (II) n=3,I=2,ml=1,s=+21; represents 3d(n+I=5) (III) n=4,I=1,mI=0,s=+21; represents 4p(n+I=5) (IV) n=3,I=1,ml=−1,s=+21; represents 3p(n+I=4) Order of energy depends on the (n+I), greater is the (n+I) value greater is the energy, if (n+I) is same, then it depends on n; if ' n ' is more, energy is more. Step-1: According to (n+I ) Energy =(I)>(II)=( III )>(IV) Step-2 : If n↑, then energy increases Energy =(I)>( III )>( II )>( IV)
The quantum numbers of four electrons are given below : I. n=4 ; I=2 ; m_1=-2 ; s=- 1 2 II. n=3 ; I=2 ; m_1=1 ; s=+ 1 2 III. n=4 ; I=1 ; m_1=0 ; s=+…
NEET UG 2024 — Chemistry Physical Chemistry
The quantum numbers of four electrons are given below : I. n=4;I=2;m1=−2;s=−21 II. n=3;I=2;m1=1;s=+21 III. n=4;I=1;m1=0;s=+21 IV. n=3;I=1;m1=−1;s=+21 The correct decreasing order of energy of these electrons is
Held on 30 Apr 2024 · Verified 9 Jul 2026.
Options
- A
IV > II > III > I
- B
I > III > II > IV
- C
III > I > II > IV
- D
I > II > III > IV
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