K=Ae−Ea/RT After taking In both side lnK=lnA−RTEa InK1=lnA−RT1Ea at temp. T1...(i) InK2=lnA−RT2Ea at temp. T2,,(ii) (ii) - (i) InK2−InKK1=REa[T11−T21] ln K1K2=REa[5001−7001] ln0.040.14=REa[500×700700−500] ln414=REa[500×700200] log3.5=2.303×REa[250×71] 0.5441=2.303×8.31Ea[250×71] Ea=0.5441×8.31×250×7×2.303 =0.5441×83.1×25×7×2.303 =18222.65 ≈18219 J