2H2O(g)⟶2H2( g)+O2( g) ΔH∘=483.64 kJ For decomposition of 2 moles of H2O, enthalpy change =483.64 kJ For decomposition of 1 mole of H2O, enthalpy change =2483.64 kJ =241.82 kJ
Consider the following reaction: 2H2( g)+O2( g)→2H2O(g)ΔrH∘=−483.64 kJ. What is the enthalpy change for decomposition of one mole of water? (Choose the right option).
Held on 30 Apr 2023 · Verified 9 Jul 2026.
18 kJ
100 kJ
120.9 kJ
241.82 kJ
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