Explanation: 4 A+3 B⟶6C+9D Rate of reaction =−41dtd[ A]=−31dtd[ B]=61dtd[C]=91dtd[D] Rate of reaction = Rate of formation of C. ∴r=61dtd[C]=61×6×10−2=1×10−2 mol L−1 s−1 Also, rate of reaction = Rate of disappearance of B r=−31dtd[ B]=dtd[ B]=3×r=3×10−2 mol L−1 s−1 Consumption of B in 10 seconds =3×10−2×10 =30×10−2 mol L−1