Explanation: 4 A+3 B⟶6C+9D Rate of reaction =−41dtd[ A]=−31dtd[ B]=61dtd[C]=91dtd[D] Rate of reaction = Rate of formation of C. ∴r=61dtd[C]=61×6×10−2=1×10−2 mol L−1 s−1 Also, rate of reaction = Rate of disappearance of B r=−31dtd[ B]=dtd[ B]=3×r=3×10−2 mol L−1 s−1 Consumption of B in 10 seconds =3×10−2×10 =30×10−2 mol L−1
For a chemical reaction 4 ~A+3 ~B → 6 C+9 D rate of formation of C is 6 × 10^-2 ~mol ~L^-1 ~s^-1 and rate of disappearance of A is 4 × 10^-2 ~mol…
NEET UG 2022 — Chemistry Physical Chemistry
For a chemical reaction 4 A+3 B→6C+9D rate of formation of C is 6×10−2 mol L−1 s−1 and rate of disappearance of A is 4×10−2 mol L−1 s−1. The rate of reaction and amount of B consumed in interval of 10 seconds, respectively will be:
Held on 30 Apr 2022 · Verified 9 Jul 2026.
Options
- A
1×10−2 mol L−1 s−1 and 30×10−2 mol L−1
- B
10×10−2 mol L−1 s−1 and 10×10−2 mol L−1
- C
1×10−2 mol L−1 s−1 and 10×10−2 mol L−1
- D
10×10−2 mol L−1 s−1 and 30×10−2 mol L−1
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