Λm∞(CH3COOH)=Λm∞(CH3COONa)+Λm∞(HCl)−Λm∞(NaCl)
=91+426.16−126.45
=390.71Scm2mol−1
The molar conductance of NaCl,HCl and CH3COONa at infinite dilution are 126.45,426.16 and 91.0Scm2mol−1 respectively. The molar conductance of CH3COOH at infinite dilution is. Choose the right option for your answer.
Held on 30 Apr 2021 · Verified 9 Jul 2026.
201.28Scm2mol−1
390.71Scm2mol−1
698.28Scm2mol−1
540.48Scm2mol−1
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