Number of atoms =molarmassw×NA×atomicity
Number of atoms in 1g of Li(s) = 71×NA×1
Number of atoms 1g of Ag(s) =1081×NA×1
Number of atoms 1g of Mg(s) = 241×NA×1
Number of atoms 1g of O2(g) = 321×NA×2
NEET UG 2020 — Chemistry Physical Chemistry
Which one of the followings has maximum number of atoms?
Held on 30 Apr 2020 · Verified 9 Jul 2026.
1g of Mg(s) [Atomic mass of Mg=24]
1g of O2(g) [Atomic mass of O=16]
1g of Li(s) [Atomic mass of Li=7]
1g of Ag(s) [Atomic mass of Ag=108]
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