Assuming dilute solution,
PsP0−Ps≈P0P0−Ps=nsolvent nsolute
Let P0=100, V.P reduced to 80
100100−80=114/1148/m
m=40 g/mol.
NEET UG 2020 — Chemistry Physical Chemistry
If 8g of a non-electrolyte solute is dissolved in 114g of n−octane to reduce its vapour pressure to 80 the molar mass (in gmol−1) of the solute is [Given that molar mass of n-octane is 114gmol−1]
Held on 30 Apr 2020 · Verified 9 Jul 2026.
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