NaOH is a strong base, thus [OH−]pOH=0.0M=10−2M=−log[OH−]=−log(10−2)=2 We know that, pH+pOH=14 ∴pH=14−2=12 Thus, option (3) is correct.
NEET UG 2019 — Chemistry Physical Chemistry
The pH of 0.01MNaOH(aq) solution will be
Held on 30 Apr 2019 · Verified 9 Jul 2026.
7.01
2
12
9
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