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The molar solubility of CaF_2 ( K_ sp=5.3 × 10^-11 ) in 0.1 M solution of NaF will be

NEET UG 2019 — Chemistry Physical Chemistry

2019mcqmedium

The molar solubility of CaF2\mathrm{CaF}_2CaF2​ (Ksp=5.3×10−11)\left(\mathrm{K}_{\mathrm{sp}}=5.3 \times 10^{-11}\right)(Ksp​=5.3×10−11) in 0.1M0.1 \mathrm{M}0.1M solution of NaF\mathrm{NaF}NaF will be

Official previous-year question

Held on 30 Apr 2019 · Verified 9 Jul 2026.

Options

  1. A

    5.3×1011 mol L−15.3 \times 10^{11} \mathrm{~mol} \mathrm{~L}^{-1}5.3×1011 mol L−1

  2. B

    5.3×10−8 mol L−15.3 \times 10^{-8} \mathrm{~mol} \mathrm{~L}^{-1}5.3×10−8 mol L−1

  3. C

    5.3×10−9 mol L−15.3 \times 10^{-9} \mathrm{~mol} \mathrm{~L}^{-1}5.3×10−9 mol L−1

  4. D

    5.3×10−10 mol L−15.3 \times 10^{-10} \mathrm{~mol} \mathrm{~L}^{-1}5.3×10−10 mol L−1

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