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For a cell involving one electron E_cell°leddash =0.59 V at 298 K, the equilibrium constant for the cell reaction is: [Given that 2.303 RT F=0.059 V…

NEET UG 2019 — Chemistry Physical Chemistry

2019mcqmedium

For a cell involving one electron Ecell⊝=0.59V{E}_{cell}^{\circleddash }=0.59 VEcell⊝​=0.59V at 298K298 K298K, the equilibrium constant for the cell reaction is:

[Giventhat2.303RTF=0.059VatT=298K][Given that \frac{2.303 RT}{F}=0.059 V at T=298 K][GiventhatF2.303RT​=0.059VatT=298K]

Official previous-year question

Held on 30 Apr 2019 · Verified 9 Jul 2026.

Options

  1. A

    1.0×1021.0\times {10}^{2}1.0×102

  2. B

    1.0×1051.0\times {10}^{5}1.0×105

  3. C

    1.0×10101.0\times {10}^{10}1.0×1010

  4. D

    1.0×10301.0\times {10}^{30}1.0×1030

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