Key Idea According to Kohlrausch's law, λm0 for AxBy=xλ(A)0+0+yλ(B)x− where, λm∘= limiting molar conductivity of electrolyte and λ(A)y+0 and λ(B)x−0 are the limiting molar conductivities of cation (Ay+) and anion (Bx−), respectively. 
Following limiting molar conductivities are given as given as … λ_ m ( CH_2 COOK )^0= Z S cm ^2 ~mol^-1
NEET UG 2019 — Chemistry Physical Chemistry
2019mcqhard
Following limiting molar conductivities are given as given as λm(H2SO4)0=xScm2 mol−1λm(K2SO4)0=yScm2 mol−1 λm(CH2COOK)0=ZScm2 mol−1
Official previous-year question
Held on 30 Apr 2019 · Verified 9 Jul 2026.
Options
- A
x−y+2z
- B
x+y−z
- C
x−y+z
- D
2(x−y)+z
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