ΔU=q+w
For adiabatic process, q=0
∴ΔU=w
=−P⋅ΔV
=−2.5atm×(4.5−2.5)L
=−2.5×2L−atm
=−5×101.3J
=−506.5J
≈−505J
NEET UG 2017 — Chemistry Physical Chemistry
A gas is allowed to expand in a well-insulated container against a constant external pressure of2.5atm from an initial volume of 2.50L to a final volume of 4.50L. The change in internal energy ΔU of the gas in joules will be
Held on 30 Apr 2017 · Verified 9 Jul 2026.
1136.25J.
−500J.
−505J.
+505J.
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