Pt,H+H2(g) Hydrogen electrode EH2/H+o=0.0Volt
H2(g)→2H(aq)++2e−
[H+]=10−7M at 25oC (for Pure water)
E=2−0.0591log(PH2[H+]2)
E=0=logPH2[H+]=0
∴[H+]2=PH2=(10−7)2
∴PH2=10−14atm
NEET UG 2016 — Chemistry Physical Chemistry
The pressure of H2 required to make the potential of hydrogen electrode zero in pure water at 298 K is:
Held on 30 Apr 2016 · Verified 9 Jul 2026.
10−14atm
10−12atm
10−10atm
10−4atm
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