t=0t=eqC5H5N+H2OCC(1−α)⇌C5H5N⊕HCα+OH⊖Cα
∴Kb=1−αCα2≈Cα2
∴α=CKb=0.11.7×10−9
=1.3×10−4
∴
NEET UG 2016 — Chemistry Physical Chemistry
The percentage of pyridine (C5H5N) that forms pyridinium ion (C5H5N+H) in a 0.10M aqueous pyridine solution (KbforC5H5N=1.7×10−9) is
Held on 30 Apr 2016 · Verified 9 Jul 2026.
0.0060
0.013
0.77
1.6
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