At 100oC (boiling point)
Vapour pressure of water Po=Patm=760mm
∴PoPo−Ps=Xsolute
⇒760760−732=nsolventnsolutem=molarmassofsolute
⇒73228=100/186.5/m
⇒m=28×1006.5×18×732≈30.6
Now,
ΔTb=Kb×molality
=0.52×0.16.5/30.6=1.1∘C
∴ Boiling point of solution =100+1.1=101.1oC≃101∘C