N1V1−N2V2=N.V.
0.1×1−0.01×1=N×2
[OH−]=Nnet=20.09=0.045N
pOH=−log(0.045)=1.35
∴pH=14−pOH=14−1.35=12.65
What is the pH of the resulting solution when equal volumes of 0.1 M NaOH and 0.01 M HCl are mixed?
Held on 30 Apr 2015 · Verified 9 Jul 2026.
12.65
2.0
7.0
1.04
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