Mass of 1 mol (6.022×1023atoms) of carbon = 12g
If Avogadro Number (NA) is changed then mass of 1 mol (6.022×1020atom) of carbon
=6.022×102312×6.022×1020=12×10−3g
NEET UG 2015 — Chemistry Physical Chemistry
If Avogadro number NA , is changed from 6.022×1023mol−1 to 6.022×1020mol−1 , this would change:
Held on 30 Apr 2015 · Verified 9 Jul 2026.
The definition of mass in units of grams
The mass of one mole of carbon
The ratio of chemical species to each other in a balanced equation.
The ratio of elements to each other in a compound.
Sign in to track your attempts and accuracy.
Sign in to keep a private note on this question. Nothing you write is ever public.
The unit of rate constant for a first-order reaction is:
For the reaction 2SO₂(g) + O₂(g) ⇌ 2SO₃(g), ΔH = -198 kJ. Which condition favours forward reaction?
The standard heat of formation, in $\mathrm{kcal} / \mathrm{mol}^{\text {of }} \mathrm{Ba}^{2+}$ is : [Given : standard heat of formation of $\mathrm{SO}_4^{2-}$ ion (aq) $=-216 \mathrm{kcal} / \mathrm{mol}$, Standard heat of crystallisation of $\mathrm{BaSO}_4(\mathrm{~s})=-4.5 \mathrm{kcal} / \mathrm{mol}$, standard heat of formation of $\left.\mathrm{BaSO}_4(\mathrm{~s})=-349 \mathrm{kcal} / \mathrm{mol}\right]$
Match List - I with List - II $\begin{array}{llll} & \begin{array}{l} \text { List-I } \\ \text { (Example) } \end{array} & & \begin{array}{l} \text { List-II } \\ \text { (Type of Solution) } \end{array} \\ \text { A. } & \text { Humidity } & \text { I. } & \text { Solid in solid } \\ \text { B. } & \text { Alloys } & \text { II. } & \text { Liquid in gas } \\ \text { C. } & \text { Amalgams } & \text { III. } & \text { Solid in gas } \\ \text { D. } & \text { Smoke } & \text { IV. } & \text { Liquid in solid } \end{array}$ Choose the correct answer from the options given below:
The conjugate base of H₂SO₄ is:
Work through every NEET UG Physical Chemistry PYQ, year by year.