NEET UG 2015 — Chemistry Physical Chemistry

2015mcqhard

Assuming complete ionization, same moles of which of the following compounds will require the least amount of acidified $KMn{O}_{4}$ for complete oxidation?

Official previous-year question

Held on 30 Apr 2015 · Verified 9 Jul 2026.

Options

A
$FeS{O}_{4}$
B
$FeS{O}_{3}$
C
$Fe{C}_{2}{O}_{4}$
D
$Fe{(N{O}_{2})}_{2}$

Did you get this right?

Solution

${MnO}_{4}^{-}\longrightarrow M{n}^{2+}$ ; Change in oxidation no. = 5

In option,

i. $F{e}^{2+} \longrightarrow F{e}^{3+}$

Change in oxidation no. = 1

ii. $F{e}^{2+} \longrightarrow F{e}^{3+}$

Change in oxidation no. = 1

${SO}_{3}^{2-}\longrightarrow {SO}_{4}^{2-}$

Change in oxidation no. = 2

$=1+2=3$

iii. $F{e}^{2+} \longrightarrow F{e}^{3+}$

Change in oxidation no. = 1

${C}_{2}{O}_{4}^{2-}\longrightarrow 2C{O}_{2}$

Change in oxidation no. = 2

$=1+2=3$

iv. $F{e}^{2+} \longrightarrow F{e}^{3+}$

Change in oxidation no. = 1

$2{NO}_{2}^{-}\longrightarrow 2{NO}_{3}^{-}$

Change in oxidation no. = 4

$=1+4=5$

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NEET UG 2015 — Chemistry Physical Chemistry

2015mcqhard

Assuming complete ionization, same moles of which of the following compounds will require the least amount of acidified $KMn{O}_{4}$ for complete oxidation?

Official previous-year question

Held on 30 Apr 2015 · Verified 9 Jul 2026.

Options

A
$FeS{O}_{4}$
B
$FeS{O}_{3}$
C
$Fe{C}_{2}{O}_{4}$
D
$Fe{(N{O}_{2})}_{2}$

Did you get this right?

Solution

${MnO}_{4}^{-}\longrightarrow M{n}^{2+}$ ; Change in oxidation no. = 5

In option,

i. $F{e}^{2+} \longrightarrow F{e}^{3+}$

Change in oxidation no. = 1

ii. $F{e}^{2+} \longrightarrow F{e}^{3+}$

Change in oxidation no. = 1

${SO}_{3}^{2-}\longrightarrow {SO}_{4}^{2-}$

Change in oxidation no. = 2

$=1+2=3$

iii. $F{e}^{2+} \longrightarrow F{e}^{3+}$

Change in oxidation no. = 1

${C}_{2}{O}_{4}^{2-}\longrightarrow 2C{O}_{2}$

Change in oxidation no. = 2

$=1+2=3$

iv. $F{e}^{2+} \longrightarrow F{e}^{3+}$

Change in oxidation no. = 1

$2{NO}_{2}^{-}\longrightarrow 2{NO}_{3}^{-}$

Change in oxidation no. = 4

$=1+4=5$

Your note

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NEET UG 2015 — Chemistry Physical Chemistry

Options

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Solution

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NEET UG Physical Chemistry in other years

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NEET UG 2015 — Chemistry Physical Chemistry

Options

Did you get this right?

Solution

Your note

NEET UG Physical Chemistry in other years

More NEET UG Physical Chemistry questions

Other Chemistry topics for NEET UG

Organic Chemistry

Inorganic Chemistry

Keep practicing Physical Chemistry