ΔH=ΔU+ΔngRT
=2.1+10002×2×300=3.3kcal
ΔG=ΔH−TΔS
=3.3−300×100020=3.3−6=−2.7kcal
NEET UG 2014 — Chemistry Physical Chemistry
For the reaction:
X2O4(l)→2XO2(g)
ΔU=2.1kcal,ΔS=20calK−1 at 300K
Hence, ΔG is:
Held on 30 Apr 2014 · Verified 9 Jul 2026.
2.7kcal
−2.7kcal
9.3kcal
−9.3kcal
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