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For the reaction: X_2 O_4(l)→ 2XO_2(g) Δ U=2.1 k cal, Δ S=20 cal K^-1 at 300 K Hence, Δ G is:

NEET UG 2014 — Chemistry Physical Chemistry

2014mcqhard

For the reaction:

X2O4(l)→2XO2(g){X}_{2}{O}_{4}(l)\rightarrow 2X{O}_{2}(g)X2​O4​(l)→2XO2​(g)

ΔU=2.1kcal,ΔS=20calK−1\Delta U=2.1 k \mathrm{cal}, \Delta S=20 \mathrm{cal} {K}^{-1}ΔU=2.1kcal,ΔS=20calK−1 at 300K300 K300K

Hence, ΔG\Delta GΔG is:

Official previous-year question

Held on 30 Apr 2014 · Verified 9 Jul 2026.

Options

  1. A

    2.7kcal2.7 k cal2.7kcal

  2. B

    −2.7kcal-2.7 k cal−2.7kcal

  3. C

    9.3kcal9.3 k cal9.3kcal

  4. D

    −9.3kcal-9.3 k cal−9.3kcal

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