Given, number of molecules of urea =6.02×1020 ∴ Number of moles =NA6.02×1020=6.02×10236.02×1020=1×10−3 mol Volume of the solution =100 mL=1000100 L=0.1 L Concentration of urea solution ( in molL−1)=0.11×10−3molL−1=1×10−2 mol L−1=0.01 mol L−1
6.02 × 10^20 molecules of urea are present in 100 ~mL of its solution. The concentration of solution is
NEET UG 2013 — Chemistry Physical Chemistry
6.02×1020 molecules of urea are present in 100 mL of its solution. The concentration of solution is
Held on 30 Apr 2013 · Verified 9 Jul 2026.
Options
- A
0.02M
- B
0.01M
- C
0.001M
- D
0.1M
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