Millimoles solution of chloride = 0.05×10=0.5 Millimoles of AgNO3=10×0.1= 0.1. XCl2+2AgNO3→2AgCl+X(NO3)2
In an experiment it is shown that 10 ml of 0.05 M solution of chloride required 10 ml of 0.1 M solution of AgNO_3, which of the following will be the…
NEET UG 2013 — Chemistry Physical Chemistry
In an experiment it is shown that 10ml of 0.05M solution of chloride required 10 ml of 0.1M solution of AgNO3, which of the following will be the formula of the chloride ( X stands for the symbol of the element other than chlorine)
Held on 30 Apr 2013 · Verified 9 Jul 2026.
Options
- A
X2Cl2
- B
XCl2
- C
XCl4
- D
X2Cl
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