Given, molarity of solution =2 Volume of solution =250 mL=1000250=41 L Molar mass of HNO3=1+14+3×16=63 g mol−1 ∵ Molarity = mass of HNO3× volume of solution ( L) weight of HNO3∴ Weight of HNO3= molarity × mol. mass × volume (L)=2×63×41 g=31.5 g It is the weight of 100%HNO3. But the given acid is 70%HNO3. ∴ Its weight =31.5×70100 g=45 g