If n=1, E1=−2.178×10−18Z2 J If n=6 E6=36−2.178×10−18Z2 J=6.05×10−20Z2 J From the above calculation, it is abvious that electron has a more negative energy than it does for n=6. It means that electron is more strongly bound in the smallest allowed orbit.
Based on equation E=-2.178 × 10^-18 ~J ( Z^2 n^2 ) certain conclusions are written. Which of them is not correct?
NEET UG 2013 — Chemistry Physical Chemistry
2013mcqeasy
Based on equation E=−2.178×10−18 J(n2Z2) certain conclusions are written. Which of them is not correct?
Official previous-year question
Held on 30 Apr 2013 · Verified 9 Jul 2026.
Options
- A
The negative sign in equation simply means that the energy of electron bound to the nucleus is lower than it would be if the electrons were at the infinite distance from the nucleus
- B
Larger the value of n, the larger is the orbit radius
- C
Equation can be used to calculate the change in energy when the electron changes orbit
- D
For n=1 the electron has a more negative energy than it does for n=6 which means that the electron is more loosely bound in the smallest allowed orbit
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