H+pHpH=55×10−14=−log[H+]=−log[55×10−14]=21[−log(55×10−14)]=6.13
NEET UG 2013 — Chemistry Physical Chemistry
At 100∘C the Kw of water is 55 times its value at 25∘C. What will be the pH of neutral solution? (log55=1.74)
Held on 30 Apr 2013 · Verified 9 Jul 2026.
7.00
7.87
5.13
6.13
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