NEET UG 2013 — Chemistry Physical Chemistry

The formula of dichlorotetraqua chromium (III) chloride is $\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl}$[Cr(H2​O)4​Cl2​]Cl. On ionisation it generates only one $\mathrm{Cl}^{-}$Cl−ion. $$\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right] \mathrm{Cl} \longrightarrow\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_4 \mathrm{Cl}_2\right]^{+}+\mathrm{Cl}^{-}$$[Cr(H2​O)4​Cl2​]Cl⟶[Cr(H2​O)4​Cl2​]++Cl− Initial $100 \times 0.01$100×0.01 0 $\mathrm{mmol}=1 \mathrm{mmol}$mmol=1mmol After ionisation 0 $1 \mathrm{mmol} \quad 1 \mathrm{mmol}$1mmol1mmol One mole of $\mathrm{Cl}^{-}$Cl−ions react with only 1 mole of $\mathrm{AgNO}_3$AgNO3​ molecule to produce 1 mole of $\mathrm{AgCl}$AgCl. $\therefore 1$∴1 mmol or $1 \times 10^{-3}$1×10−3 mole reacts with $\mathrm{AgNO}_3$AgNO3​ to give $\mathrm{AgCl}$AgCl $$=\frac{1 \times 1 \times 10^{-3}}{1}=10^{-3} \text { or } 0.001 \mathrm{~mol} \mathrm{AgCl}$$=11×1×10−3​=10−3 or 0.001 molAgCl