The formula of dichlorotetraqua chromium (III) chloride is [Cr(H2O)4Cl2]Cl. On ionisation it generates only one Cl−ion. [Cr(H2O)4Cl2]Cl⟶[Cr(H2O)4Cl2]++Cl− Initial 100×0.01 0 mmol=1mmol After ionisation 0 1mmol1mmol One mole of Cl−ions react with only 1 mole of AgNO3 molecule to produce 1 mole of AgCl. ∴1 mmol or 1×10−3 mole reacts with AgNO3 to give AgCl =11×1×10−3=10−3 or 0.001 molAgCl
An excess of AgNO_3 is added to 100 ~mL of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitate…
NEET UG 2013 — Chemistry Physical Chemistry
An excess of AgNO3 is added to 100 mL of a 0.01M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitate would be
Held on 30 Apr 2013 · Verified 9 Jul 2026.
Options
- A
0.001
- B
0.002
- C
0.003
- D
0.01
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