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According to law of photochemical equivalence the energy absorbed (in erg/ mole ) is given as (h=6.62 × 10^-27 . ergs, =3 × 10^10 ~cm ~s^-1, ~N_…

NEET UG 2013 — Chemistry Physical Chemistry

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According to law of photochemical equivalence the energy absorbed (in erg/ mole ))) is given as (h=6.62×10−27\left(h=6.62 \times 10^{-27}\right.(h=6.62×10−27 ergs, c=3×1010 cm s−1, NA=6.02×10−23\mathrm{c}=3 \times 10^{10} \mathrm{~cm} \mathrm{~s}^{-1}, \mathrm{~N}_{\mathrm{A}}=6.02 \times 10^{-23}c=3×1010 cm s−1, NA​=6.02×10−23 mol−1)\left.\mathrm{mol}^{-1}\right)mol−1) :

Official previous-year question

Held on 30 Apr 2013 · Verified 9 Jul 2026.

Options

  1. A

    1.196×108λ\frac{1.196 \times 10^8}{\lambda}λ1.196×108​

  2. B

    2.859×105λ\frac{2.859 \times 10^5}{\lambda}λ2.859×105​

  3. C

    2.859×1016λ\frac{2.859 \times 10^{16}}{\lambda}λ2.859×1016​

  4. D

    1.196×1016λ\frac{1.196 \times 10^{16}}{\lambda}λ1.196×1016​

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