For hydrogen electrode, oxidation half reaction is (1 atm)H2⟶(At pH 10)2H++2e− If pH=10 H+=1×10−pH=1×10−10 From Nernst equation, Ecell =Ecell 0−20.0591logPH2[H+]2 For hydrogen electrode, Ecell ∘=0 Ecell =−20.0591log1(10−10)2=+20.0591×2log10−101=0.0591log1010=0.0591×10=0.591 V
A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH=10 and by passing hydrogen gas around the platinum wire at 1…
NEET UG 2013 — Chemistry Physical Chemistry
2013mcqeasy
A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH=10 and by passing hydrogen gas around the platinum wire at 1 atm pressure. The oxidation potential of electrode would be
Official previous-year question
Held on 30 Apr 2013 · Verified 9 Jul 2026.
Options
- A
0.059 V
- B
0.59 V
- C
0.118 V
- D
1.18 V
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