Molar mass of CH2Cl2=12×1+1×2+35.5×2=85 g mol−1 Molar mass of CHCl3=12×1+1×1+35.5×3=119.5 g mol−1 Moles of CH2Cl2=40 g/85 g mol−1=0.47 mol Moles of CHCl3=25.5 g/119.5 g mol−1=0.213 mol Total number of moles =0.47+0.213=0.683 mol Mole fraction of component 2 =0.47 mol/0.683 mol=0.688 Mole fraction of component 1 =1.00−0.688=0.312 We know that: PT=p10+(p20−p10)x2=200+(415−200)×0.688=200+147.9=347.9 mmHg