For 10∘ rise in temperature, n=1 so rate =2n=21=2 When temperature is increased from 10∘C to 100∘C, change in temperature =100−10=90∘C, i.e., n=9 So, rate =29=512 times Alternate method With every 10∘ rise in temperature, rate becomes double, so rr′=2(10100−10)=29=512 times.