For 10∘ rise in temperature, n=1 so rate =2n=21=2 When temperature is increased from 10∘C to 100∘C, change in temperature =100−10=90∘C, i.e., n=9 So, rate =29=512 times Alternate method With every 10∘ rise in temperature, rate becomes double, so rr′=2(10100−10)=29=512 times.
In a zero order reaction for every 10° rise of temperature, the rate is doubled. If the temperature is increased from 10° C to 100° C, the rate of…
NEET UG 2012 — Chemistry Physical Chemistry
In a zero order reaction for every 10∘ rise of temperature, the rate is doubled. If the temperature is increased from 10∘C to 100∘C, the rate of the reaction will become
Held on 30 Apr 2012 · Verified 9 Jul 2026.
Options
- A
256 times
- B
512 times
- C
64 times
- D
128 times
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