A2(g)+B2(g)⇌2AB(g) The equilibrium constant is given by Kc=[A2][B2][AB]2=(3.0×10−3)(4.2×10−3)(2.8×10−3)2=12.67.84=0.62
NEET UG 2012 — Chemistry Physical Chemistry
Given the reaction between two gases represented by A2 and B2 to give the compound AB(g). A2(g)+B2(g)⇌2AB(g) At equilibrium, the concentration of A2=3.0×10−3M of B2=4.2×10−3M of AB=2.8×10−3M If the reaction takes place in a sealed vessel at 527∘C, then the value of Kc will be
Held on 30 Apr 2012 · Verified 9 Jul 2026.
2.0
1.9
0.62
4.5
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