Total pressure, pT=pA′+pB′ We know that, pA′=pAxA pB′=pBxB Substituting the values of pA′ and pB′ in Eq. (i) pT[xA+xB∴pT=pAxA+pBxB=1⇒xA=1−xB or xB=1−xA]=pAxA+pB(1−xA)=pAxA+pB−pBxA=pB+xA(pA−pB)
p_A and p_B are the vapour pressure of pure liquid components, A and B, respectively of an ideal binary solution. If x_A represents the mole fraction…
NEET UG 2012 — Chemistry Physical Chemistry
pA and pB are the vapour pressure of pure liquid components, A and B, respectively of an ideal binary solution. If xA represents the mole fraction of component A, the total pressure of the solution will be
Held on 30 Apr 2012 · Verified 9 Jul 2026.
Options
- A
pA+xA(pB−pA)
- B
pA+xA(pA−pB)
- C
pB+xA(pB−pA)
- D
pB+xA(pA−pB)
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