Initial moles : Moles at eq. : 2A(g)11−(2×0.25)=0.5+B(g)11−0.25=0.75⇌3C(g)03×0.25=0.75+D(g)00.25=0.25 Equilibrium constant, K=[A]2[B][C]3[D] ∴K=(0.5)2(0.75)(0.75)3(0.25)
NEET UG 2010 — Chemistry Physical Chemistry
The reaction, 2 A(g)+B(g)⇋3C(g)+D(g) is begun with the concentrations of A and B both at an initial value of 1.00 M When equilibrium is reached, the concentration of D is measured and found to be 0.25 M. The value for the equilibrium constant for this reaction is given by the expression
Held on 30 Apr 2010 · Verified 9 Jul 2026.
[(0.75)3(0.25)]÷[(1.00)2(1.00)]
[(0.75)3(0.25)]÷[(0.50)2(0.75)]
[(0.75)3(0.25)]÷[(0.50)2(0.25)]
[(0.75)3(0.25)]÷[(0.75)2(0.25)]
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