ΔGΔGΔHT=ΔH−TΔS=0( given )=TΔS,=108.840.63×103=373.4 K
For vaporisation of water at 1 atm pressure, the values of ΔH and ΔS are 40.63 kJ mol−1 and 108.8JK−1 mol−1, respectively. The temperature when Gibbs energy change (ΔG) for this transformation will be zero, is
Held on 30 Apr 2010 · Verified 9 Jul 2026.
273.4 K
393.4 K
373.4 K
293.4 K
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