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For vaporisation of water at 1 ~atm pressure, the values of Δ H and Δ S are 40.63 ~kJ ~mol^-1 and 108.8 JK^-1 ~mol^-1, respectively. The temperature…

NEET UG 2010 — Chemistry Physical Chemistry

2010mcqmedium

For vaporisation of water at 1 atm1 \mathrm{~atm}1 atm pressure, the values of ΔH\Delta \mathrm{H}ΔH and ΔS\Delta SΔS are 40.63 kJ mol−140.63 \mathrm{~kJ} \mathrm{~mol}^{-1}40.63 kJ mol−1 and 108.8JK−1 mol−1108.8 \mathrm{JK}^{-1} \mathrm{~mol}^{-1}108.8JK−1 mol−1, respectively. The temperature when Gibbs energy change (ΔG)(\Delta G)(ΔG) for this transformation will be zero, is

Official previous-year question

Held on 30 Apr 2010 · Verified 9 Jul 2026.

Options

  1. A

    273.4 K273.4 \mathrm{~K}273.4 K

  2. B

    393.4 K393.4 \mathrm{~K}393.4 K

  3. C

    373.4 K373.4 \mathrm{~K}373.4 K

  4. D

    293.4 K293.4 \mathrm{~K}293.4 K

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