Let the order of reaction with respect to A is x and with respect to B is y. Thus, rate =k[A]x[B]y For the given cases, (I) rate =k(0.1)x(0.1)y=6.0×10−3 (II) rate =k(0.3)x(0.2)y=7.2×10−2 (III) rate =k(0.3)x(0.40)y=2.88×10−1 (IV) rate =k(0.4)x(0.1)y=2.40×10−2 On dividing Eq. (I) by (IV), we get (0.40.1)x(0.10.1)y=2.4×10−26.0×10−3 or (41)x=(41)1 ∴x=1 On dividing Eq. (II) by (III), we get or or ∴(0.30.3)x(0.40.2)y(21)y(21)yy=2.88×10−17.2×10−2=41=(21)2=2 ∴ Thus, rate law is, rate =k[A]1[ B]2 or =k[A][B]2
During the kinetic study of the reaction, 2 ~A+ B → C+ D, following results were obtained … Based on the above data which one of the following is…
NEET UG 2010 — Chemistry Physical Chemistry
During the kinetic study of the reaction, 2 A+B→C+D, following results were obtained Run I II III IV [A]/mol L−10.10.30.30.4[B]/mol L−10.10.20.40.1Initial rate offormation ofD/mol L−1 min−16.0×10−37.2×10−22.88×10−12.40×10−2 Based on the above data which one of the following is correct?
Held on 30 Apr 2010 · Verified 9 Jul 2026.
Options
- A
rate =k[A]2[ B]
- B
rate =k[A][B]
- C
rate =k[A]2[ B]2
- D
rate =k[A][B]2
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