Ecell = cathode D− (red) Eanode ∘or Ecell = cred) Ecathode ∘+ (oxide) EAnode ∘or Ecell = (oxide) E anode E−Ecathode ∘ (oxide)
NEET UG 2010 — Chemistry Physical Chemistry
Consider the following relations for emf of a electrochemical cell (A) Emf of cell = (oxidation potential of anode) - (reduction potential of cathode) (B) Emf of cell = (oxidation potential of anode) + (reduction potential of cathode) (C) Emf of cell = (reduction potential of anode) + (reduction potential of cathode) (D) Emf of cell = (oxidation potential of anode)-(Oxidation potential of cathode) Which of the above relations are correct?
Held on 30 Apr 2010 · Verified 9 Jul 2026.
(C) and (A)
(A) and (B)
(C) and (D)
(B) and (D)
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