Number of milliequivalents of HCl =20×0.050×1=1 Number of milliequivalents of Ba(OH)2 =2×30×0.10=6 [OH−]of final solution milliequivalents of Ba(OH)2= total volume − milliequivalents of HCl=506−1=0.1M
What is the [OH−]in the final solution prepared by mixing 20.0 mL of 0.050MHCl with 30.0 mL of 0.10MBa(OH)2 ?
Held on 30 Apr 2009 · Verified 9 Jul 2026.
0.10M
0.40M
0.0050M
0.12M
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